Scrabble Australia
Tournaments:
2005:
QLD:
23.10.2005 Mindbenders Standard
:
Joan Watson
[Main] [Ratings] [Stats]
Joan Watson Wins: 3
Aggregate: 2380
Ranking: 13th of 28
Average for: 396.66
Average against: 407.16
Pre-tournament rating: 1454
Post-tournament rating: 437 |
| Round | Opponent | Scores | Margin | Wins | Σ Aggregate | |
|---|---|---|---|---|---|---|
| 1 | Denver Brodsky (1257) | 369 | 319 | 50 | 1 | 369 |
| 2 | Kay Hamilton (1327) | 464 | 374 | 90 | 2 | 833 |
| 3 | Joy McGowan (1405) | 452 | 449 | 3 | 3 | 1285 |
| 4 | Olga Visser (1507) | 286 | 435 | -149 | 3 | 1571 |
| 5 | Fay Grose (1309) | 383 | 403 | -20 | 3 | 1954 |
| 6 | Linda Williams (1178) | 426 | 463 | -37 | 3 | 2380 |
| Legend: | Bye | Win | Loss | Draw | Scheduled |